52-[3c+4]=4[c+6]+c

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Solution for 52-[3c+4]=4[c+6]+c equation:


Simplifying
52 + -1[3c + 4] = 4[c + 6] + c

Reorder the terms:
52 + -1[4 + 3c] = 4[c + 6] + c
52 + [4 * -1 + 3c * -1] = 4[c + 6] + c
52 + [-4 + -3c] = 4[c + 6] + c

Combine like terms: 52 + -4 = 48
48 + -3c = 4[c + 6] + c

Reorder the terms:
48 + -3c = 4[6 + c] + c
48 + -3c = [6 * 4 + c * 4] + c
48 + -3c = [24 + 4c] + c

Combine like terms: 4c + c = 5c
48 + -3c = 24 + 5c

Solving
48 + -3c = 24 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
48 + -3c + -5c = 24 + 5c + -5c

Combine like terms: -3c + -5c = -8c
48 + -8c = 24 + 5c + -5c

Combine like terms: 5c + -5c = 0
48 + -8c = 24 + 0
48 + -8c = 24

Add '-48' to each side of the equation.
48 + -48 + -8c = 24 + -48

Combine like terms: 48 + -48 = 0
0 + -8c = 24 + -48
-8c = 24 + -48

Combine like terms: 24 + -48 = -24
-8c = -24

Divide each side by '-8'.
c = 3

Simplifying
c = 3

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